Linear continuum
link author: James Munkres (via WP:JWB)
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A [[Set (mathematics)|set]] has the least upper bound property, if every nonempty subset of the set that is bounded above has a least upper bound in the set. Linear continua are particularly important in the field of [[topology]] where they can be used to verify whether an [[total order|ordered set]] given the [[order topology]] is [[Connected space|connected]] or not.{{cite book|last=Munkres|first=James|title=Topology |
A [[Set (mathematics)|set]] has the least upper bound property, if every nonempty subset of the set that is bounded above has a least upper bound in the set. Linear continua are particularly important in the field of [[topology]] where they can be used to verify whether an [[total order|ordered set]] given the [[order topology]] is [[Connected space|connected]] or not.{{cite book|last=Munkres|first=James|author-link=James Munkres|title=Topology|ed=2nd|year=2000|publisher=[[Pearson Education]]|isbn=0-13-181629-2|pages=31,153}} |
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Unlike the standard real line, a linear continuum may be bounded on either side: for example, any (real) [[closed interval]] is a linear continuum. |
Unlike the standard real line, a linear continuum may be bounded on either side: for example, any (real) [[closed interval]] is a linear continuum. |
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==Topological properties== |
==Topological properties== |
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Even though linear continua are important in the study of [[total order|ordered sets]], they do have applications in the mathematical field of [[topology]]. In fact, we will prove that an ordered set in the [[order topology]] is [[Connected space|connected]] if and only if it is a linear continuum. We will prove one implication, and leave the other one as an exercise. (Munkres explains the second part of the proof in {{cite book|last=Munkres|first=James|title=Topology |
Even though linear continua are important in the study of [[total order|ordered sets]], they do have applications in the mathematical field of [[topology]]. In fact, we will prove that an ordered set in the [[order topology]] is [[Connected space|connected]] if and only if it is a linear continuum. We will prove one implication, and leave the other one as an exercise. (Munkres explains the second part of the proof in {{cite book|last=Munkres|first=James|author-link=James Munkres|title=Topology|ed=2nd|year=2000|publisher=Pearson Education|isbn=0-13-181629-2|pages=153–154}}) |
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'''Theorem''' |
'''Theorem''' |
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